I'm fairly good with practical math, but never got much into Statistics. Now I have a dinky little problem that's driving me nuts. My grandson popped this one on me. It's part of his high school homework. I not only couldn't figure it out. I couldn't googleate it. It would have been a snap with coins, because everybody has stuff on the Net about coin probabilities. I'm hoping there's somebody out there in Monkeyland that can make the solution to this problem as simple as I wish it was. Here's the problem: To Sit With the Captain: A Ship’s Pool Question On a ship, a daily pool will be held each day for six days. Tickets will be sold for each pool. Each ticket buys one number in one daily pool. A passenger can pick the number they want in each pool. A passenger can buy as many tickets as they wish for each pool—but only before the ship sails. Whoever wins all six pools gets to sit at the Captain’s table for the rest of the voyage. The first pool has 23 numbers. The second pool has 27 numbers. The third pool has 33 numbers. On fourth pool has 34 numbers. The fifth pool has 29 numbers. The sixth pool has 20 numbers. Q1: What are the chances of a passenger winning all six pools with a total of six tickets? Q2: How many tickets would a passenger have to buy to be certain of winning all six pools? I am seriously monkey-stumped here. Any help would be much appreciated.